Suggested: expand (2/x-x/2)^5 using binomial theorem - (2/x-x/2)^5 - 10/x+y+2/x-y=4 15/x+y-5/x-y=-2 - 2/x+3/y=13 5/x-4/y=-2 - 5/x-1+1/y-2=2 6/x-1-3y-2=1 - find the perimeter of the loop of the curve 9ay^2=(x-2a)(x-5a)^2 - 3(x-2)2(x+5)=3(x+1)2(x-1)+3 - (x+2)(x+3)(x+4)(x+5)/(x-2)(x-3)(x-4)(x-5)=1 - 5 x 2+4=2(x+2) - (2 x x 2)^5 Browse related:
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